(x^2+3)^2=4x^2+12

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Solution for (x^2+3)^2=4x^2+12 equation: 



(x^2+3)^2=4x^2+12

We move all terms to the left:

(x^2+3)^2-(4x^2+12)=0

We get rid of parentheses

-4x^2+(x^2+3)^2-12=0

We move all terms containing x to the left, all other terms to the right

-4x^2+(x^2+3)^2=12

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